The equation of the curve passing through the origin and satisfying the differential equation (1x 2) dxdy 2xy=4x 2 is Medium View solution > Solve ( y 3 x 2) d y d x = x Medium View solution > The solution of the equation (xy) dy (xy) dx =0 isSolution for X^24y^24xy1=0 equation Simplifying X 2 4y 2 4xy 1 = 0 Reorder the terms 1 X 2 4xy 4y 2 = 0 Solving 1 X 2 4xy 4y 2 = 0 Solving for variable 'X' Move all terms containing X to the left, all other terms to the right Add '1' to each side of the equation 1 X 2 4xy 1 4y 2 = 0 1 Reorder the terms 1 1 X 2 4xy 4y 2 = 0 1 CombineIdentical expressions (x^ two)y' (x^ two)(y^ two) four xy 4= zero (x squared )y stroke first (1st) order plus (x squared )(y squared ) minus 4xy plus 4 equally 0

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(x y)^2-4xy formula
(x y)^2-4xy formula-Answer (1 of 2) > > x = y cosec^2x = 4xy(xy)^2 4xy = (xy)^2 (xy)^2 So , Our Equation can be written as => cosec^2x = ((xy)^2 (xy)^2)/(xy)^2 =>cosec^2x = 1Degree 2 the quadratic polynomials x2−y2 and xyare harmonic;




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Solution for X^24xyy^2=0 equation Simplifying X 2 4xy y 2 = 0 Solving X 2 4xy y 2 = 0 Solving for variable 'X' Move all terms containing X to the left, all other terms to the right Add '4xy' to each side of the equation y = arctan(x)/(1x^2)^2 C/(1x^2)^2 We have (1x^2)y'4xy=(1x^2)^2 A We can rearrange A as follows (1x^2)y'4xy = 1/(1x^2)^2 dy/dx (4x)/(1x^2)y = 1/(1x^2)^3 B We can use an integrating factor when we have a First Order Linear nonhomogeneous Ordinary Differential Equation of the form;1 4x2y p x y = 4xy2 x y 1 dy dx = (4xy2 p x y) 1 1 4x2y p x y 7Find all the xcoordinates of the points on the curve x2y2 xy= 2 where the slope of the tangent line is 1 We need to nd the derivative dy dx by implicit di erentiation Di erentiating with respect to xon both sides of the equation, 2xy2 x2 2y dy dx y x dy dx = 0 Here
This differential equation is called an Euler differential equation We seek solutions of the form y(x) = xr y ( x) = x r Substituting yields an algebraic equation for r r of the form a2r(r−10 0 View solution steps Solution Steps 2xy (5x (3x)) (2x (4xy2xy)) 2 x y − ( 5 x − ( 3 x)) − ( − 2 x − ( − 4 x y 2 x y)) Combine 5x and 3x to get 2x Combine 5 x and − 3 x to get 2 xThe new equation is exact since M y = N x = 4xy 2x Now integrate Mand N Z M(x;y)dx= Z (2xy 2 2xy 4x3)dx= xy2 x2y x4 g(y);
Answer (1 of 7) There are many method or ways to solve this question METHOD1 so if know the formula (XY) ^2=(XY) ^2 4XY Substituting the values We get 11^2=(XY) ^2 23 121 23 = (XY) ^2 144 = (XY) ^2 Therefore (XY) = 12 METHOD 2 IfCombine 2xy and 4xy to get 2xy x^ {2}\left (2y\right)xy^ {2}=0 All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction Consider the system of linear equations in x, y, z (sin 3θ) x y z = 0 (cos 2θ) x 4y 3z = 0 asked in Mathematics by Amita ( 5k points) trigonometrical equations




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Solve the differential equation (x^2 6y^2) dx 4xy dy = 0 when x= 1 y= 1 using at least three methods Question Solve the differential equation (x^2 6y^2) dx 4xy dy = 0 when x= 1 y= 1 using at least three methodsSec 2 θ = 4xy/(x y) 2 is true if and only if 1) x y ≠ 0 2) x = y, x ≠ 0 3) x = y 4) x ≠ 0, y ≠ 0 Answer (2) x = y, x ≠ 0 Solution Given, sec 2 θ = 4xy/(x y) 2 We know that, sec 2 θ ≥ 1 Therefore, 4xy/(x y)2 ≥ 1Q The equation $14x^2 4xy 11y^2 = 60$ represents a certain locus If the axes are rotated through an angle $\tan^{1} \, 2$, without change of origin then the equation of the locus referred to new axes becomes




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To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Show that the equation `sec^2 theta=(4xy)/(xy)^2` is only possible when x=ySolve (x^2 1)y" 4xy' 2y = 2/x 1 such that the general solution obeys the initial conditions y (0) = 1 and y' (0) = 5 and given that y_1 = 1/x 1 and y_2 = 1/x 1 are solutions to the homogeneous version As a check to our sanity we should try to do the same problem in two different ways to make sure everything is working correctlyPlease be sure to answer the questionProvide details and share your research!




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X^2*y x^2 y' = 0;Example 1 Determine the critical points and locate any relative minima, maxima and saddle points of function f defined by f(x , y) = 2x 2 2xy 2y 2 6x Solution to Example 1 Find the first partial derivatives f x and f y f x (x,y) = 4x 2y 6 f y (x,y) = 2x 4y The critical points satisfy the equations f x (x,y) = 0 and f y (x,y) = 0 simultaneously HenceIf negative, an ellipse;




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(a) the new formula fo rq=x 2 y2 (b) the old formula fo rq=XY (c) the equation of the circle x 2 y2 = 1 in the new system 9 In the usual x,y coord system, q is 2x 2 3xy4y2 Switch to a new X,Y coord system which has the same axes as before but new scales If the old scale was the inch, on the new Xaxis use the foot and on the new YaxisCalculus Find dy/dx x^24xyy^2=4 x2 4xy y2 = 4 x 2 − 4 x y y 2 = 4 Differentiate both sides of the equation d dx (x2 4xy y2) = d dx(4) d d x ( x 2 − 4 x y y 2) = d d x ( 4) Differentiate the left side of the equation Tap for more stepsEquation at the end of step 1 Step 2 Equation at the end of step 2 Step 3 x 2 3xy 10y 2 Simplify ——————————————— x 2 4xy 5y 2 Trying to factor a multi variable polynomial 31 Factoring x 2 3xy 10y 2 Try to factor this



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